| 本站網友 Arjay ip:188.143.232.* |
2016-09-02 19:28:30 發表 |
| I’m not sure I understood you.What do you mean by “. So reading track one more time to let the error float away seems to be all ri2h.tRg1; ???I only need to read each track exactly once to get a good copy of it. Now, if it doesn’t pass checksum, then, of course, I can re-read it.The 5 or 6 bad bits no longer occur since I’ve fixed the code. So everything comes out perfect now.Is this what you meant? |
| |
|
| 本站網友 Clara ip:188.143.232.* |
2016-08-29 03:51:54 發表 |
| This is a really intlneigelt way to answer the question. |
| |
|
網友評論僅供網友表達個人看法，并不表明本站同意其觀點或證實其描述
|